The ionization energy of H atom is - 13.6   e V . The energy required for exciting the electron in a H atom from the ground state to the first excited state is ( A v o g a d r o ’ s   c o n s t a n t =   6.022   ×   10 23 )

Step-by-step solution

Ionization energy denotes the minimum amount of energy required to remove an electron from an atom or molecule in the gaseous state. Value of orbit number in n th excited state = n + 1 Example : n = 2 for first excited state. E 2 = - 13.6 n 2 = - 13.6 4 = - 3.4   e V We know that energy required for excitation from n = 1 to n = 2 : Δ E = E 2 - E 1 = - 3.4 - ( - 13.6 ) = 10.2   e V Therefore, energy required for excitation of electron per atom = 10.2 6.02 × 1 0 23 = 1.69 × 1 0 - 23   J