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An electron moving with velocity 'v' is found to have a certain value of de-Broglie wavelength. The velocity to be possessed by the neutron to have the same de-Broglie wavelength is

Options

  1. A1 8 4 0 v
  2. B1840 v
  3. Cv 1 8 4 0
  4. Dv

Correct answer

C. v 1 8 4 0

Step-by-step solution

λ e = h m e v λ m = h m n v n ∴ λ e = λ n ∴ 1 m e v = 1 m n v n or V n v = m e m n = 9.1 × 10 − 28 1.67 × 10 − 24 = 1 1840 or v n = 1 1 8 4 0 × v = v 1 8 4 0

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