How does the probability distribution curve for 2s electron appears?

Step-by-step solution

(a) is a correct answer because R 2 is always +ve and there is one node in 2s orbital. (b) is not possible because there is no node (c) is possible if we plot r with 4 πr 2 R (d) is not possible because a 2 cannot be negative it is obtained when 'r' is plotted with 'R'. 2s total nodes = n − l − 1 = 2 − 0 − 1 = 1