99 Percentile Qs Bank for JEE MainChemistryStructure of Atom
An electronic transition in hydrogen atom results in the formation of H _ line of hydrogen in Lyman series, the energies associated with the electron in each of the orbits involved in the transition (in kcal mol ⁻¹ ) are
Options
- A-313.6,-34.84
- B-313.6,-78.4
- C-78.4,-34.84
- D-78.4,-19.6
Correct answer
B. -313.6,-78.4
Step-by-step solution
Energy of an electron in n^ th orbit, E_n=- 2 ^2 k^2 m Z^2 e^4 n^2 h^2 On substituting the values of k, m, e and h , we get aligned E_n & =- 2.172 10⁻¹⁸ Z^2 m^2 ~J ^2 atom ⁻¹ or & =- 1311.8 Z^2 n^2 ~kJ ~mol ⁻¹ or & =- 313.52 Z^2 n^2 kcal mol ⁻¹ & [ 1 kcal =4.184 ~kJ ] aligned For H-atom, Z=1 For Lyman series, n₁=1, n₂=2 Energy of electron in n₁ orbit aligned & =- 313.52 (1)^2 (1)^2 kcal mol ⁻¹ & =-313.52 kcal mol ⁻¹ & -313.6 kcal mol ⁻¹ aligned Energy of electron in n₂ orbit aligned & =- 313.52 (1)^2 (2)^2 kcal mol