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The sum of angular node and angular momentum for ψ 432 is

Options

  1. A6 h + 3 π 2 π
  2. B3 h + π 2 π
  3. C3 h + 3 π π
  4. D3 h + 3 π 3 π

Correct answer

C. 3 h + 3 π π

Step-by-step solution

ψ 432 ⇒ n = 4 , l = 3 , m = 2 ∴ number of angular nodes = l = 3 And orbital angular momentum = l l + 1 h 2 π = 12 h 2 π = 3 h π This gives 'C' as correct answer

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