99 Percentile Qs Bank for JEE MainMathematicsHyperbola
The equation of the chord of the hyperbola 25 x 2 - 16 y 2 = 400 , which is bisected at the point ( 6 , 2 ) , is
Options
- A16 x - 75 y = 418
- B75 x - 16 y = 418
- C25 x - 4 y = 400
- DNone of these
Correct answer
B. 75 x - 16 y = 418
Step-by-step solution
Given equation of hyperbola is 25 x 2 - 16 y 2 = 400 . If ( 6 , 2 ) is the mid-point of the chord, then equation of chord is T = S 1 . ⇒ 25 6 x - 16 2 y - 400 = 25 36 - 16 ( 4 ) - 400 ⇒ 75 x - 16 y = 418 .