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If one of the roots of the equation x^2-5 x-14=0 is the length of the semi conjugate axis of the hyperbola x^2 a^2 - y^2 b^2 =1 and the square of the other root is the semi-transverse axis then the focus of the hyperbola that lies on the positive x -axis is

Options

  1. A(5,0)
  2. B( 65 , 0)
  3. C(7,0)
  4. D( 74 , 0)

Correct answer

B. ( 65 , 0)

Step-by-step solution

Given equation is x^2-5 x-14=0 how roots are -2,7 Let b=7 and a=4 hence C= 7^2+9^2 = 65 hence S=( 65 , 0)

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