The figure shows a capacitor of capacitance $C$ connected to a battery via a switch, having a total charge $Q$ on it, in steady-state. When the switch $S$ is turned from position $A$ to position $B$ , the energy dissipated in the circuit is

Question

The figure shows a capacitor of capacitance

C

connected to a battery via a switch, having a total charge

Q

on it, in steady-state. When the switch

S

is turned from position $A$ to position

B

, the energy dissipated in the circuit is

The figure shows a capacitor of capacitance C connected to a battery via a switch, having a total charge Q on it, in

The figure shows a capacitor of capacitance C connected to a battery via a switch, having a total charge Q on it, in

Quantrex Academy · Accepted Answer

Correct answer: B. (3)/(8)(Q2)/(C)

Q _ 0 = Cε (Q1)/(C) = (Q2)/(3C) Q _ 1 + Q _ 2 = Q _ 0 ⇒ Q _ 1 = (Q0)/(4); Q _ 2 = 3 Q _ 0 4 Energy dissipated, E = (1)/(2) Q _ 0 ^ 2 C - (1)/(2) Q _ 1 ^ 2 C - (1)/(2) Q _ 2 ^ 2 3C = (1)/(2C) ( Q _ 0 ^ 2 - Q _ 0 ^ 2 16 - 9 Q _ 0 ^ 2 3 × 16 ) = Q _ 0 ^ 2 32C( 16 - 1 - 3) = (3)/(8) Q _ 0 ^ 2 C

The figure shows a capacitor of capacitance C connected to a...

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