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For a screw gauge least count of the main scale is 1 m m . Find the minimum number of divisions on the circular scale so that it can measure a diameter of 5 μm

Options

  1. A500
  2. B100
  3. C50
  4. D200

Correct answer

D. 200

Step-by-step solution

Least count of screw gauge = 5 μm L . C = pitch no . of div on circular scale 5 μm = 1 mm N N = 200

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