Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app

JEE Main

Exam: JEE Main
Subject: Physics
Chapter: Experimental Physics

JEE Main · Physics · Experimental Physics

For a screw gauge least count of the main scale is 1mm . Find the...

For a screw gauge least count of the main scale is

1mm .

Find the minimum number of divisions on the circular scale so that it can measure a diameter of

5\mu m

Options

A $500$
B $100$
C $50$
D $200$

Correct answer

D. $200$

Step-by-step solution

Least count of screw gauge

= 5\mu m

L . C = \dfrac{pitch}{no . ofdivoncircularscale}

5\mu m = \dfrac{1mm}{N}

N = 200

Practice Experimental Physics on Quantrex Academy →

More from Experimental Physics

Two thin wires, Wire-1 of diameter 0.650 mm and Wire-2 of unknown diameter d are given.… JEE Advanced 2026 In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is… JEE Main 2026 In a screw gauge when the circular scale is given five complete rotations it moves… JEE Main 2026 In a screw gauge the zero of main scale reference line coincides with the fifth division… JEE Main 2026 In an experiment, a set of reading are obtained as follows - 1.24 ~mm, 1.25 ~mm, 1.23 ~mm… JEE Main 2026 When both jaws of vernier callipers touch each other, zero mark of the vernier scale is… JEE Main 2026 In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions.… JEE Main 2026 In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal… JEE Main 2026 Full Experimental Physics list All 99 Percentile Qs Bank for JEE Main PYQs