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The figure shows two diagrams of the same screw gauge. In the first case, nothing is kept in its jaw and in the second case a small ball is kept between the jaws for which the diameter is required to be measured. The number of circular divisions on the shown screw gauge is 50 . It moves 0 . 5 mm on the main scale for one complete rotation and the main scale has 1 2 mm marks. The diameter of the ball is

Options

  1. A2.25 mm
  2. B2.20 mm
  3. C1.20 mm
  4. D1.25 mm

Correct answer

C. 1.20 mm

Step-by-step solution

Pitch = 0.5 mm L.C = 0.5 50 = 0.01 mm M.S.R = 2 Neck reading = 25 d = 2 × 0.5 + 25 × 0.01 = 1.25 mm Considering zero error Here zero error is = + 5 × 0.01 = + 0.05 mm so actual diameter = d - 0.05 = 1.20 mm

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