99 Percentile Qs Bank for JEE MainPhysicsExperimental Physics
The figure shown below is a screwgauge. When the circular scale division matches the main scale at 43, the 6 . 5 m m mark on the main scale is just visible. The main scale has 1 2 mm marks. In complete rotation, the screw advances by 1 2 mm and circular scale has 50 divisions. The reading of the screwgauge is
Options
- A6 . 93 mm
- B5 . 93 mm
- C4 . 93 mm
- D7 . 93 mm
Correct answer
A. 6 . 93 mm
Step-by-step solution
Object thickness = 6.5 mm + 4 3 1 / 2 mm 5 0 = 6.93 mm