A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with a kinetic energy E 0 2 . The total energy of explosion is

Step-by-step solution

It is given that a stationary body explodes into four identical fragments such that three of them fly oft mutually perpendicular to each other, each with kinetic energy E 0 2 . Let the speed of each of them be v So. 1 2   m v 2 = E 0 2 Using the principle of conservation of energy, the speed of the fourth fragment v ' = v 2 + v 2 + v 2 = 3   v Its kinetic energy, E ' = 1 2   m   3   v 2 = 3 2   m v 2 = 3 2   E 0 Hence the total energy produced by the explosion is, E ' + 3 × E