99 Percentile Qs Bank for JEE MainPhysicsRotational Motion
A pendulum is oscillating with an angular amplitude of 90 ° as shown in the figure. The value of angle α , made by the string with the vertical, at which the acceleration is directed horizontally is
Options
- A0
- B90 °
- Ccos - 1 1 3
- Dsin - 1 1 3
Correct answer
C. cos - 1 1 3
Step-by-step solution
For horizontal acceleration, net force in vertical direction should be zero. Loss in potential energy = gain in kinetic energy m g h = 1 2 m v 2 m g l cos α = 1 2 m v 2 ∴ v = 2 g l cos α ∵ The net force towards O is T - m g cos α = m v 2 l = m 2 g l cos α l = 2 m g cos α ∴ T = 3 m g cos α ∴ T cos α = m g Or 3 m g c o s 2 α = m g ∴ α = c o s - 1 1 3