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99 Percentile Qs Bank for JEE MainPhysicsRotational Motion

A small ball B of mass m is suspended with light inelastic string of length L from a block A of same mass m which can move on smooth horizontal surface as shown in the figure. The ball is displaced by angle θ from equilibrium position & then released. The displacement of centre of mass of A + B system till the string becomes vertical is

Options

  1. AZero
  2. BL 2 1 - cos θ
  3. CL 2 1 - sin θ
  4. DNone of these

Correct answer

B. L 2 1 - cos θ

Step-by-step solution

Δ y CM = - mL 1 - cos  θ + 0 m + m = L 2 1 - cos  θ

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