A simple pendulum of length 2 ~m is given a horizontal push through angular displacement of 60^ . If the mass of bob is 200 gram, the angular velocity of the bob will be (Take Acceleration due to gravity =10 ~m / s ^2 ) ( 30^ = 60^ =0.5, 30^ = 60^ = 3 / 2 )

Step-by-step solution

Given: l=2 ~m , =60^ , m =200 ~g =2 ~g From the figure, T = mr ^2 ... (i) also T = mg ... (ii) putting (i) into (ii) mr ^2- = mg ... (iii) putting the given values into equation (iii) aligned & 2 2 ^2 1 2 =2 10 . ( 60= 1 2 ) & ^2=10 & = 10 .( 10 = 2 2 2.5 ) & =2 2.5 rad / s aligned