A seconds pendulum clock having steel wire is calibrated at 20 ° C . When temperature is increased to 30 ° C , then calculate how much time does the clock lose or gain in one week α steel = 1 . 2 × 1 0 - 5 ∘ C -1

Step-by-step solution

The time period of the second's pendulum = 2 s Change in the time period, Δ T = 1 2 T α Δ θ Δ T = 1 2 2 1 . 2 × 1 0 - 5 3 0 ∘ - 2 0 ∘ = 1 . 2 × 1 0 - 4 s New time period, T ′ = T + Δ T T ′ = 2 . 0 0 0 1 2 s Time lost in a week, Δ t = Δ T T ′ × t = 1 . 2 × 1 0 - 4 2 . 0 0 0 1 2 × 7 × 2 4 × 3 6 0 0 = 3 6 . 2 8 s