99 Percentile Qs Bank for JEE MainPhysicsThermal Properties of Matter
A wall is made of equally thick layers P and Q of different materials. Thermal conductivity of Q is half of that of the P . In the steady state, if the temperature difference across the wall is 24^ C , then the temperature difference across the layer ' P ' is ............... .
Options
- A12^ C
- B16^ C
- C4^ C
- D8^ C
Correct answer
D. 8^ C
Step-by-step solution
We have, array ll K_Q= K_P 2 K_P=2 K_Q & 2 K_Q a (T₁-T₀ ) x = K_Q a (T₀-T₂ ) x x & [ [ Q t ]_P= [ Q t ]_Q ] 2 (T₁-T₀ )=T₀-T₂ & array According to the question, Now, from Eq. (i), aligned & 2 T₁-3 T₀+T₁-24=0 & 3 T₁-3 T₀=24 T₁-T₀=8^ C aligned