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A copper block of mass 2 . 5   kg is heated in furnace to a temperature of 500 °   C and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper is 0 . 30   J   ( g - K ) - 1 ; heat of fusion of water is 335   J   g - 1 )

Options

  1. A1 . 5
  2. B2
  3. C2 . 1
  4. D3

Correct answer

A. 1 . 5

Step-by-step solution

Given, mass of copper block m = 2 . 5   kg Change in temperature Δ t = 5 0 0 ° C Specific heat s = 0 . 39   J   ( g - K ) - 1 = 390   J   ( kg - K ) - 1 Latent heat of fusion of water L = 335   J   g - 1 =   335 × 10 3   J   kg - 1 Heat energy absorbed by copper block Q 1 = ms Δ t = 2 . 5 × 390 × 500   J Let m ' kg   of ice be melted. Heat energy required to melt ice, Q 2 = m ' L But heat energy absorbed by copper block is Hea

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