In an adiabatic process, the pressure is increased by 2 3 % and C p C v = 3 2 for the gas. Then the volume decreases by about:

Step-by-step solution

For an adiabatic process, PV γ = K Here, γ = 3 / 2 and K = constant ∴ PV 3 / 2 = K log P + 3 2 log V = log K Δ P P + 3 2 Δ V V = 0 ∴ Δ V V = - 2 3 Δ P P Δ V V × 1 0 0 = - 2 3 Δ P P × 1 0 0 = - 2 3 × 2 3 = - 4 9 Therefore volume decreases by about 4 9 % .