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99 Percentile Qs Bank for JEE MainPhysicsThermodynamics

An ideal gas is subjected to cyclic process involving four thermodynamic states, the amounts of heat (Q) and work (W) involved in each of these states are aligned & Q₁=6000 ~J , Q₂=-5500 ~J ; Q₃=-3000 ~J ; & Q₄=3500 ~J & W₁=2500 ~J ; W₂=-1000 ~J ; W₃=-1200 ~J ; & W₄=x ~J . aligned The ratio of the net work done by the gas to the total heat absorbed by the gas is . The values of x and respectively are

Options

  1. A500 ; 7.5 %
  2. B700 ; 10.5 %
  3. C1000 ; 21 %
  4. D1500 ; 15 %

Correct answer

C. 1000 ; 21 %

Step-by-step solution

From first law of thermodynamics aligned & Q= U+W & or U=Q-W & U₁=Q₁-W₁=6000-2500=3500 ~J & U₂=Q₂-W₂=-5500+1000=-4500 ~J aligned aligned & U₃=Q₃-W₃=-3000+1200=-1800 ~J & U₄=Q₄-W₄=3500-x aligned For cyclic process U=0 aligned & 3500-4500-1800+3500-x=0 & or & x=700 ~J & Efficiency, = output input 100 & = W₁+W₂+W₃+W₄ Q₁+Q₄ 100 & = (2500-1000-1200+700) 6000+3500 100 & = 1000 9500 100 & =10.5 % & aligned

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