99 Percentile Qs Bank for JEE MainPhysicsThermodynamics
A monoatomic ideal gas goes through a cyclic process as shown in the figure. The efficiency of this process is
Options
- A19.04 %
- B42 %
- C62 %
- D21 %
Correct answer
A. 19.04 %
Step-by-step solution
(No options match) Work done in complete cycle = Area under closed curve =2 P V Heat given to the system from A to B=n C_V T =n 3 2 R T= 3 2 V P= 3 2 V (3 P-P)=3 P V Similarly, heat given to the system from B to C aligned & =n C_P T & =n ( 5 2 R ) T= 5 2 (3 P)( V) & = 5 2 (3 P) (2 V-V)= 15 2 P V aligned The heat is released from C to D and D to A . Efficiency ( )= Work done by gas Heat given to gas 100 = 2 P V 3 P V+ 15 2 P V 100= 4 21 100=19.04 %