The diagram shows the adiabatic curve for n moles of an ideal gas. The bulk modulus for the gas corresponding to the point P will be

Step-by-step solution

For adiabatic process : Bulk modulus : B = γ P For point P : P = nRT V = nR 3 T 0 3 V 0 = nRT 0 V 0 ⇒ B = γ nRT 0 V 0 ...(i) Now, TV γ - 1 = constant ⇒ γ - 1 TdV + VdT = 0 ⇒ dV dT = - V γ - 1 T For point P → - 3 V 0 3 T 0 = - 3 V 0 γ - 1 3 T 0 ⇒ γ = 2 So, from Eq. (i), B = 2 nRT 0 V 0