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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Centre of Mass, Linear momentum, Collision

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Centre of Mass, Linear momentum, Collision

A railroad car of mass M initially rests on frictionless rails. A...

A railroad car of mass MM initially rests on frictionless rails. A man of mass mm starts moving towards the engine on the car. If the car recoils backward along the rails with a speed vv, determine the velocity at which the man approaches the engine.

Options

  1. A\left(1 + \dfrac{m}{M}\right)v
  2. B\left(\dfrac{m}{M}\right)v
  3. C\left(\dfrac{M}{m}\right)v
  4. D\left(1 + \dfrac{M}{m}\right)v

Correct answer

D. \left(1 + \dfrac{M}{m}\right)v

Step-by-step solution

Let the velocity of the man relative to the ground be vmv_m and the velocity of the car relative to the ground be vc=−vv_c = -v.

Since no external horizontal force acts on the system, the total linear momentum is conserved.

mvm+Mvc=0m v_m + M v_c = 0

mvm−Mv=0m v_m - M v = 0

vm=Mmvv_m = \dfrac{M}{m} v

The velocity at which the man approaches the engine is his velocity relative to the car.

vrel=vm−vcv_{rel} = v_m - v_c

vrel=Mmv−(−v)v_{rel} = \dfrac{M}{m} v - (-v)

vrel=(1+Mm)vv_{rel} = \left(1 + \dfrac{M}{m}\right) v
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