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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Centre of Mass, Linear momentum, Collision

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Centre of Mass, Linear momentum, Collision

A ball having a mass of 0.50 kg and travelling at a speed of 5.0...

A ball having a mass of 0.50 kg0.50 \text{ kg} and travelling at a speed of 5.0 m/s5.0 \text{ m/s} collides with another ball of mass 1.0 kg1.0 \text{ kg}. Following the collision, the two stick together and stay motionless. Determine the velocity of the 1.0 kg1.0 \text{ kg} block prior to the collision.

Options

  1. A2.5 m/s2.5 \text{ m/s} opposite to the direction of motion of the first ball
  2. B1.25 m/s1.25 \text{ m/s} opposite to the direction of motion of the first ball
  3. C5.0 m/s5.0 \text{ m/s} opposite to the direction of motion of the first ball
  4. D2.5 m/s2.5 \text{ m/s} in the direction of motion of the first ball

Correct answer

A. 2.5 m/s2.5 \text{ m/s} opposite to the direction of motion of the first ball

Step-by-step solution

According to the law of conservation of linear momentum, the total momentum before the collision is equal to the total momentum after the collision.

m1v1+m2v2=(m1+m2)vfm_1 v_1 + m_2 v_2 = (m_1 + m_2) v_f

Given m1=0.50 kgm_1 = 0.50 \text{ kg}, v1=5.0 m/sv_1 = 5.0 \text{ m/s}, m2=1.0 kgm_2 = 1.0 \text{ kg}, and vf=0v_f = 0.

Substituting the values:

0.50×5.0+1.0×v2=(0.50+1.0)×00.50 \times 5.0 + 1.0 \times v_2 = (0.50 + 1.0) \times 0

2.5+v2=02.5 + v_2 = 0

v2=−2.5 m/sv_2 = -2.5 \text{ m/s}

The negative sign indicates that the velocity of the second ball is opposite to the direction of motion of the first ball.
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