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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Circular Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Circular Motion

A simple pendulum is suspended from the ceiling of a car executing...

A simple pendulum is suspended from the ceiling of a car executing a turn of radius 10 m10 \text{ m} at a speed of 36 km/h36 \text{ km/h}. Determine the angle made by the pendulum's string with the vertical, given that this angle remains constant throughout the turn. Take g=10 m/s2g = 10 \text{ m/s}^2.

Options

  1. A45^{}^{{}^{\circ}}
  2. B60^{}^{{}^{\circ}}
  3. C30^{}^{{}^{\circ}}
  4. D37^{}^{{}^{\circ}}

Correct answer

A. 45^{}^{{}^{\circ}}

Step-by-step solution

Given speed of the car, v=36 km/h=36×518 m/s=10 m/sv = 36 \text{ km/h} = 36 \times \dfrac{5}{18} \text{ m/s} = 10 \text{ m/s}

Radius of the turn, r=10 mr = 10 \text{ m}

Centripetal acceleration of the car is ac=v2r=10210=10 m/s2a_c = \dfrac{v^2}{r} = \dfrac{10^2}{10} = 10 \text{ m/s}^2

In the frame of the car, the pendulum bob experiences a pseudo force horizontally outward and the gravitational force downwards.

Balancing the forces in the frame of the car, with TT as the tension in the string and θ\theta as the angle it makes with the vertical:

Tsin⁡θ=macT \sin\theta = m a_c

Tcos⁡θ=mgT \cos\theta = mg

Dividing the two equations:

tan⁡θ=acg\tan\theta = \dfrac{a_c}{g}

Substituting the values of aca_c and gg:

tan⁡θ=1010=1\tan\theta = \dfrac{10}{10} = 1

θ=45∘\theta = 45^{{}^{{}^{\circ}}}
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