Concepts Of Physics MCQ Edition [Volume 1]PhysicsNewton's Laws of Motion
A monkey is climbing on a rope that passes over a smooth light pulley and supports a block of equal mass at the other end, as shown in the figure. Assume that initially both were at rest. Irrespective of the force the monkey exerts on the rope, which of the following correctly describes the motion of the monkey and the block?
Options
- AThe monkey and the block move in the same direction with equal acceleration, and their separation will not cha
- BThe block moves with a greater acceleration than the monkey, and their separation will increase as time passes
- CThe monkey moves with a greater acceleration than the block, and their separation will decrease as time passes
- DThe monkey and the block move in opposite directions with equal acceleration, and their separation will increa
Correct answer
A. The monkey and the block move in the same direction with equal acceleration, and their separation will not cha
Step-by-step solution
Let the mass of the monkey and the block be m . Let T be the tension in the rope. Since the pulley is smooth and light, the tension remains the same on both sides of the rope. The forces acting on the block are the tension T upwards and its weight mg downwards. The equation of motion for the block is: T - mg = m a_b where a_b is the upward acceleration of the block. The forces acting on the monkey are the tension T upwards (since the force the monkey exerts on the rope equals the tension) and its weight mg downward