An athlete requires 2.0 s to reach his maximum speed of 18.0 km/h . Determine the magnitude of his average acceleration in m/s^2 .

Correct answer: C. 2.5 Initial velocity, u = 0 Final velocity, v = 18.0 km/h = 18.0 × (5)/(18) m/s = 5.0 m/s Time taken, t = 2.0 s Average acceleration, a = (v - u)/(t) a = (5.0 - 0)/(2.0) = 2.5 m/s^2

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

An athlete requires 2.0 s to reach his maximum speed of 18.0 km/h ....

An athlete requires

2.0 \text{ s}

to reach his maximum speed of

18.0 \text{ km/h}

. Determine the magnitude of his average acceleration in

\text{m/s}^2

Options

A $9.0$
B $5.0$
C $2.5$
D $18.0$

Correct answer

C. $2.5$

Step-by-step solution

Initial velocity,

u = 0

Final velocity,

v = 18.0 \text{ km/h} = 18.0 \times \dfrac{5}{18} \text{ m/s} = 5.0 \text{ m/s}

Time taken,

t = 2.0 \text{ s}

Average acceleration,

a = \dfrac{v - u}{t}

a = \dfrac{5.0 - 0}{2.0} = 2.5 \text{ m/s}^2

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