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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

The figure displays the speed of a car as a function of time....

The figure displays the speed of a car as a function of time. Determine the distance travelled by the car in 88 seconds and its acceleration.
The figure displays the speed of a car as a function of time. Determine the distance travelled by the car in 8 seconds

Options

  1. A80 m80 \text{ m}, 2.5 m/s22.5 \text{ m/s}^2
  2. B80 m80 \text{ m}, 5.0 m/s25.0 \text{ m/s}^2
  3. C160 m160 \text{ m}, 5.0 m/s25.0 \text{ m/s}^2
  4. D160 m160 \text{ m}, 2.5 m/s22.5 \text{ m/s}^2

Correct answer

A. 80 m80 \text{ m}, 2.5 m/s22.5 \text{ m/s}^2

Step-by-step solution

The distance travelled by the car is given by the area under the speed-time graph.

Distance=12×base×height\text{Distance} = \dfrac{1}{2} \times \text{base} \times \text{height}

Distance=12×8×20=80 m\text{Distance} = \dfrac{1}{2} \times 8 \times 20 = 80 \text{ m}

The acceleration of the car is equal to the slope of the speed-time graph.

Acceleration=ΔvΔt=20−08−0=2.5 m/s2\text{Acceleration} = \dfrac{\Delta v}{\Delta t} = \dfrac{20 - 0}{8 - 0} = 2.5 \text{ m/s}^2
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