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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

The figure presents the graph of velocity versus time for a...

The figure presents the graph of velocity versus time for a particle going along the X-axis. Determine the acceleration in m/s2\text{m/s}^2.
The figure presents the graph of velocity versus time for a particle going along the X-axis. Determine the acceleration

Options

  1. A0.80.8
  2. B0.60.6
  3. C1.01.0
  4. D0.20.2

Correct answer

B. 0.60.6

Step-by-step solution

From the given velocity-time graph, the velocity at t=0t = 0 is u=2 m/su = 2 \text{ m/s}.

The velocity at t=10 st = 10 \text{ s} is v=8 m/sv = 8 \text{ m/s}.

The acceleration of the particle is equal to the slope of the v−tv-t graph:

a=ΔvΔt=8−210−0a = \dfrac{\Delta v}{\Delta t} = \dfrac{8 - 2}{10 - 0}

a=610=0.6 m/s2a = \dfrac{6}{10} = 0.6 \text{ m/s}^2
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