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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

The graph of velocity versus time for a particle going along the...

The graph of velocity versus time for a particle going along the X-axis is depicted in the figure. Find the distance travelled in 00 to 10 s10 \text{ s} in meters.
The graph of velocity versus time for a particle going along the X-axis is depicted in the figure. Find the distance

Options

  1. A3030
  2. B2020
  3. C8080
  4. D5050

Correct answer

D. 5050

Step-by-step solution

The distance travelled by the particle is given by the area under the velocity-time graph.

The region under the graph from t=0t = 0 to t=10 st = 10\text{ s} is a trapezium with parallel sides of lengths 2 m/s2\text{ m/s} and 8 m/s8\text{ m/s}, and a height of 10 s10\text{ s}.

Distance =Area of trapezium=12×(sum of parallel sides)×time interval= \text{Area of trapezium} = \dfrac{1}{2} \times (\text{sum of parallel sides}) \times \text{time interval}

Distance =12×(2+8)×10= \dfrac{1}{2} \times (2 + 8) \times 10

Distance =12×10×10=50 m= \dfrac{1}{2} \times 10 \times 10 = 50\text{ m}
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