Concepts Of Physics MCQ Edition [Volume 1]PhysicsRest and Motion Kinematics
The velocity versus time graph for a particle going along the X-axis is illustrated in the figure. Calculate the displacement in 0 to 10 s in meters.
Options
- A50
- B100
- C30
- D80
Correct answer
A. 50
Step-by-step solution
The displacement of a particle is equal to the area under its velocity-time graph. From the given graph, the area under the curve from t = 0 to t = 10 s forms a trapezium with parallel sides v = 2 m/s and v = 8 m/s , and height t = 10 s . Displacement = Area of trapezium Displacement = 1 2 ( sum of parallel sides ) time interval Displacement = 1 2 (2 + 8) 10 Displacement = 1 2 10 10 = 50 m