Concepts Of Physics MCQ Edition [Volume 1]PhysicsRest and Motion Kinematics
Based on the velocity-time plot shown in the figure, determine the distance travelled by the particle during the first 40 seconds. Also determine the average velocity during this period.
Options
- A50 m and 0 m/s
- B0 m and 0 m/s
- C100 m and 2.5 m/s
- D100 m and 0 m/s
Correct answer
D. 100 m and 0 m/s
Step-by-step solution
The distance travelled by the particle is the total area under the velocity-time graph, taking all areas as positive. Area above the time axis ( A₁ ) from t = 0 to t = 20 s : A₁ = 1 2 20 5 = 50 m Area below the time axis ( A₂ ) from t = 20 to t = 40 s : A₂ = 1 2 20 |-5| = 50 m Total distance = A₁ + A₂ = 50 + 50 = 100 m The displacement is the net area under the velocity-time graph, considering the signs. Total displacement = A₁ - A₂ = 50 - 50 = 0 m Average velocity is the total displacement divided by the total tim