Travelling at 43.2 km/h , a person applies the brake to his scooter, producing a deceleration of 6.0 m/s ^2 . Determine how far it will travel before stopping, in meters.

Step-by-step solution

Initial velocity, u = 43.2 km/h = 43.2 5 18 m/s = 12 m/s Final velocity, v = 0 m/s Acceleration, a = -6.0 m/s ^2 Using the third equation of motion, v^2 - u^2 = 2as 0^2 - (12)^2 = 2(-6.0)s -144 = -12s s = 12 m