Travelling at 43.2 km/h , a person applies the brake to his scooter, producing a deceleration of 6.0 m/s^2 . Determine how far it will travel before stopping, in meters.

Correct answer: A. 12 Initial velocity, u = 43.2 km/h = 43.2 × (5)/(18) m/s = 12 m/s Final velocity, v = 0 m/s Acceleration, a = -6.0 m/s^2 Using the third equation of motion, v^2 - u^2 = 2as 0^2 - (12)^2 = 2(-6.0)s -144 = -12s s = 12 m

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

Travelling at 43.2 km/h , a person applies the brake to his...

Travelling at

43.2 \text{ km/h}

, a person applies the brake to his scooter, producing a deceleration of

6.0 \text{ m/s}^2

. Determine how far it will travel before stopping, in meters.

Options

A $12$
B $24$
C $155.5$
D $6$

Correct answer

A. $12$

Step-by-step solution

Initial velocity,

u = 43.2 \text{ km/h} = 43.2 \times \dfrac{5}{18} \text{ m/s} = 12 \text{ m/s}

Final velocity,

v = 0 \text{ m/s}

Acceleration,

a = -6.0 \text{ m/s}^2

Using the third equation of motion,

v^2 - u^2 = 2as

0^2 - (12)^2 = 2(-6.0)s

-144 = -12s

s = 12 \text{ m}

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