An object with a velocity of 4.0 m/s is accelerated at a rate of 1.2 m/s^2 for 5.0 s . Determine the distance travelled during this period of acceleration in m.

Correct answer: C. 35 Using the second equation of motion: s = ut + (1)/(2)at^2 Substituting the given values, u = 4.0 m/s , a = 1.2 m/s^2 , and t = 5.0 s : s = (4.0)(5.0) + (1)/(2)(1.2)(5.0)^2 s = 20.0 + (0.6)(25.0) s = 20.0 + 15.0 = 35 m

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

An object with a velocity of 4.0 m/s is accelerated at a rate of...

An object with a velocity of

4.0 \text{ m/s}

is accelerated at a rate of

1.2 \text{ m/s}^2

for

5.0 \text{ s}

. Determine the distance travelled during this period of acceleration in m.

Options

A $50$
B $15$
C $35$
D $20$

Correct answer

C. $35$

Step-by-step solution

Using the second equation of motion:

s = ut + \dfrac{1}{2}at^2

Substituting the given values,

u = 4.0 \text{ m/s}

a = 1.2 \text{ m/s}^2

, and

t = 5.0 \text{ s}

s = (4.0)(5.0) + \dfrac{1}{2}(1.2)(5.0)^2

s = 20.0 + (0.6)(25.0)

s = 20.0 + 15.0 = 35 \text{ m}

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