A particle starting from rest travels with constant acceleration. If it takes 5.0 s to reach a speed of 18.0 km/h , determine the distance travelled by the particle during this period in m.

Correct answer: D. 12.5 Initial velocity, u = 0 Final velocity, v = 18.0 km/h = 18.0 × (5)/(18) m/s = 5.0 m/s Time taken, t = 5.0 s Using the first equation of motion, v = u + at 5.0 = 0 + a(5.0) a = 1.0 m/s^2 Using the second equation of motion, s = ut + (1)/(2)at^2 s = 0 + (1)/(2)(1.0)(5.0)^2 s = (25.0)/(2) = 12.5 m

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A particle starting from rest travels with constant acceleration....

A particle starting from rest travels with constant acceleration. If it takes

5.0 \text{ s}

to reach a speed of

18.0 \text{ km/h}

, determine the distance travelled by the particle during this period in m.

Options

A $25.0$
B $45.0$
C $2.5$
D $12.5$

Correct answer

D. $12.5$

Step-by-step solution

Initial velocity,

u = 0

Final velocity,

v = 18.0 \text{ km/h} = 18.0 \times \dfrac{5}{18} \text{ m/s} = 5.0 \text{ m/s}

Time taken,

t = 5.0 \text{ s}

Using the first equation of motion,

v = u + at

5.0 = 0 + a(5.0)

a = 1.0 \text{ m/s}^2

Using the second equation of motion,

s = ut + \dfrac{1}{2}at^2

s = 0 + \dfrac{1}{2}(1.0)(5.0)^2

s = \dfrac{25.0}{2} = 12.5 \text{ m}

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