A particle starting from rest travels with constant acceleration. If it takes 5.0 s to reach a speed of 18.0 km/h , determine the average velocity during this period in m/s.

Correct answer: B. 2.5 Initial velocity, u = 0 Final velocity, v = 18.0 km/h = 18.0 × (5)/(18) m/s = 5.0 m/s For constant acceleration, the average velocity is given by: v_ avg = (u + v)/(2) v_ avg = (0 + 5.0)/(2) = 2.5 m/s

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A particle starting from rest travels with constant acceleration....

A particle starting from rest travels with constant acceleration. If it takes

5.0 \text{ s}

to reach a speed of

18.0 \text{ km/h}

, determine the average velocity during this period in m/s.

Options

A $5.0$
B $2.5$
C $9.0$
D $18.0$

Correct answer

B. $2.5$

Step-by-step solution

Initial velocity,

u = 0

Final velocity,

v = 18.0 \text{ km/h} = 18.0 \times \dfrac{5}{18} \text{ m/s} = 5.0 \text{ m/s}

For constant acceleration, the average velocity is given by:

v_{\text{avg}} = \dfrac{u + v}{2}

v_{\text{avg}} = \dfrac{0 + 5.0}{2} = 2.5 \text{ m/s}

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