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Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A ball is projected vertically upward at a speed of 50 m/s ....

A ball is projected vertically upward at a speed of

50 \text{ m/s}

. Determine the maximum height in m. Take

g = 10 \text{ m/s}^2

.

Options

A $250$
B $125$
C $5$
D $50$

Correct answer

B. $125$

Step-by-step solution

Using the equation of motion

v^2 = u^2 + 2as

.

At the maximum height, the final velocity

v = 0

.

Substituting the given values

u = 50 \text{ m/s}

and

a = -g = -10 \text{ m/s}^2

:

0 = (50)^2 - 2(10)H

20H = 2500

H = \dfrac{2500}{20} = 125 \text{ m}

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