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Concepts Of Physics MCQ Edition [Volume 1]PhysicsRest and Motion Kinematics

A ball is projected vertically upward at a speed of 50 m/s . Determine the maximum height in m. Take g = 10 m/s ^2 .

Options

  1. A250
  2. B125
  3. C5
  4. D50

Correct answer

B. 125

Step-by-step solution

Using the equation of motion v^2 = u^2 + 2as . At the maximum height, the final velocity v = 0 . Substituting the given values u = 50 m/s and a = -g = -10 m/s ^2 : 0 = (50)^2 - 2(10)H 20H = 2500 H = 2500 20 = 125 m

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