A ball is projected vertically upward at a speed of 50 m/s . Determine the time required to reach the maximum height in s. Take g = 10 m/s^2 .

Correct answer: D. 5 Given initial velocity u = 50 m/s and acceleration due to gravity g = 10 m/s^2 . At the maximum height, the final velocity of the ball becomes zero, so v = 0 . Using the first equation of motion v = u - gt : 0 = 50 - 10t 10t = 50 t = 5 s

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A ball is projected vertically upward at a speed of 50 m/s ....

A ball is projected vertically upward at a speed of

50 \text{ m/s}

. Determine the time required to reach the maximum height in s. Take

g = 10 \text{ m/s}^2

Options

A $10$
B $2.5$
C $125$
D $5$

Correct answer

D. $5$

Step-by-step solution

Given initial velocity

u = 50 \text{ m/s}

and acceleration due to gravity

g = 10 \text{ m/s}^2

.

At the maximum height, the final velocity of the ball becomes zero, so

v = 0

.

Using the first equation of motion

v = u - gt

0 = 50 - 10t

10t = 50

t = 5 \text{ s}

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