A ball is projected vertically upward at a speed of 50 m/s . Determine the speed at half the maximum height. Take g = 10 m/s ^2 .

Step-by-step solution

Initial speed u = 50 m/s Maximum height H = u^2 2g Let v be the speed at half the maximum height, h = H 2 . Using the equation of motion: v^2 = u^2 - 2gh v^2 = u^2 - 2g ( H 2 ) v^2 = u^2 - gH Substituting H = u^2 2g : v^2 = u^2 - g ( u^2 2g ) = u^2 - u^2 2 = u^2 2 v = u 2 v = 50 2 = 25 2 m/s