A ball is projected from a point on the floor at a speed of 15 m/s and an angle of 60^ with the horizontal. Decide whether it will hit a vertical wall 5 m away from the point of projection and perpendicular to the plane of projection without hitting the floor. Also determine if the answer will differ if the wall is 22 m away.

Step-by-step solution

The horizontal range of the projectile is given by R = u^2 2 g . Substituting the given values u = 15 m/s , = 60^ , and g = 9.8 m/s ^2 : R = (15)^2 (120^ ) 9.8 = 225 3 2 9.8 19.88 m Since the distance to the first wall is 5 m , which is less than the range ( 5 m For the second wall at 22 m , the distance is greater than the range ( 22 m > 19.88 m ). The ball will hit the floor before reaching this wall. Thus, it will not hit the 22 m wall without hitting the floor first. Therefore, it will hit the 5 m wall, and the