Determine the average velocity of a projectile between the instants it crosses half the maximum height. It is projected with a speed u at an angle heta with the horizontal.

Step-by-step solution

The average velocity is defined as the ratio of total displacement to total time taken. Let the two instants when the projectile crosses half the maximum height be t₁ and t₂ . Since the vertical positions at these two instants are equal, the vertical displacement is zero. The horizontal velocity of the projectile remains constant throughout the motion and is equal to u . The horizontal displacement between the two instants is x = u (t₂ - t₁) . The average velocity is v_ avg = x t = u (t₂ - t₁) t₂ - t₁ = u . The dir