Concepts Of Physics MCQ Edition [Volume 1]PhysicsRest and Motion Kinematics
A person is standing on a truck moving with a constant velocity of 14.7 m/s on a horizontal road. The man throws a ball in such a way that it returns to the truck after the truck has travelled 58.8 m . Determine the speed and the angle of projection as seen from the truck.
Options
- A24.5 m/s upward
- B19.6 m/s upward
- C9.8 m/s upward
- D14.7 m/s upward
Correct answer
B. 19.6 m/s upward
Step-by-step solution
The time taken by the truck to travel 58.8 m is given by: t = d v = 58.8 14.7 = 4 s Since the ball returns to the moving truck, its horizontal displacement relative to the truck is zero. This implies that the horizontal component of the ball's velocity relative to the truck is zero. Thus, the ball is thrown vertically upwards as seen from the truck. The time of flight of the ball is equal to the time taken by the truck, so T = 4 s . Using the formula for the time of flight of a projectile thrown vertically upwards: