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Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Dispersion and Spectra

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Dispersion and Spectra

A specific material exhibits refractive indices of 1.56 , 1.60 ,...

A specific material exhibits refractive indices of

1.56

,

1.60

, and

1.68

for red, yellow, and violet light, respectively. Determine the dispersive power of the material.

Options

A $0.24$
B $0.20$
C $0.12$
D $0.18$

Correct answer

B. $0.20$

Step-by-step solution

The dispersive power

\omega

of a material is given by the formula:

\omega = \dfrac{\mu_v - \mu_r}{\mu_y - 1}

Given the refractive indices for violet, red, and yellow light:

\mu_v = 1.68

\mu_r = 1.56

\mu_y = 1.60

Substituting the values into the formula:

\omega = \dfrac{1.68 - 1.56}{1.60 - 1}

\omega = \dfrac{0.12}{0.60}

\omega = 0.20

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