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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Dispersion and Spectra

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Dispersion and Spectra

A specific material exhibits refractive indices of 1.56 , 1.60 ,...

A specific material exhibits refractive indices of 1.561.56, 1.601.60, and 1.681.68 for red, yellow, and violet light, respectively. Evaluate the angular dispersion produced by a thin prism with an angle of 6^{}^{{}^{\circ}} constructed from this material.

Options

  1. A0.12^{}^{{}^{\circ}}
  2. B3.60^{}^{{}^{\circ}}
  3. C4.08^{}^{{}^{\circ}}
  4. D0.72^{}^{{}^{\circ}}

Correct answer

D. 0.72^{}^{{}^{\circ}}

Step-by-step solution

The angular dispersion produced by a thin prism is given by the difference in the angles of deviation for violet and red light.

The formula for angular dispersion is θ=(μv−μr)A\theta = (\mu_v - \mu_r)A

Given values are μv=1.68\mu_v = 1.68, μr=1.56\mu_r = 1.56, and A = 6^{}^{{}^{\circ}}

Substituting the values into the formula:

\theta = (1.68 - 1.56) \times 6^{}^{{}^{\circ}}

\theta = 0.12 \times 6^{}^{{}^{\circ}}

\theta = 0.72^{}^{{}^{\circ}}
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