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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Dispersion and Spectra

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Dispersion and Spectra

Three thin prisms are combined as shown in the figure. The...

Three thin prisms are combined as shown in the figure. The refractive indices for red, yellow, and violet rays are μr\mu_r, μy\mu_y, and μv\mu_v respectively for the crown glass, and μr′\mu_r', μy′\mu_y', and μv′\mu_v' respectively for the flint glass. Determine the ratio A′/AA'/A such that there is no net angular dispersion.
Three thin prisms are combined as shown in the figure. The refractive indices for red, yellow, and violet rays are μ_r

Options

  1. Aμv−μr2(μv′−μr′)\dfrac{\mu_v - \mu_r}{2(\mu_v' - \mu_r')}
  2. B2(μv−μr)μv′−μr′\dfrac{2(\mu_v - \mu_r)}{\mu_v' - \mu_r'}
  3. Cμv′−μr′2(μv−μr)\dfrac{\mu_v' - \mu_r'}{2(\mu_v - \mu_r)}
  4. D2(μv′−μr′)μv−μr\dfrac{2(\mu_v' - \mu_r')}{\mu_v - \mu_r}

Correct answer

B. 2(μv−μr)μv′−μr′\dfrac{2(\mu_v - \mu_r)}{\mu_v' - \mu_r'}

Step-by-step solution

The angular dispersion produced by a single thin prism of refracting angle AA is given by θ=(μv−μr)A\theta = (\mu_v - \mu_r)A.

The given combination consists of two identical crown glass prisms (each with angle AA) and one flint glass prism (with angle A′A'). The flint glass prism is placed inverted relative to the crown glass prisms.

The total angular dispersion of the combination is the sum of the dispersions of the individual prisms. Since the flint prism is inverted, its dispersion will be in the opposite direction:

θnet=θcrown+θflint+θcrown\theta_{\text{net}} = \theta_{\text{crown}} + \theta_{\text{flint}} + \theta_{\text{crown}}

θnet=(μv−μr)A−(μv′−μr′)A′+(μv−μr)A\theta_{\text{net}} = (\mu_v - \mu_r)A - (\mu_v' - \mu_r')A' + (\mu_v - \mu_r)A

θnet=2(μv−μr)A−(μv′−μr′)A′\theta_{\text{net}} = 2(\mu_v - \mu_r)A - (\mu_v' - \mu_r')A'

For no net angular dispersion, θnet=0\theta_{\text{net}} = 0:

2(μv−μr)A−(μv′−μr′)A′=02(\mu_v - \mu_r)A - (\mu_v' - \mu_r')A' = 0

(μv′−μr′)A′=2(μv−μr)A(\mu_v' - \mu_r')A' = 2(\mu_v - \mu_r)A

A′A=2(μv−μr)μv′−μr′\dfrac{A'}{A} = \dfrac{2(\mu_v - \mu_r)}{\mu_v' - \mu_r'}
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