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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Dispersion and Spectra

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Dispersion and Spectra

A thin prism is constructed from a material with refractive indices...

A thin prism is constructed from a material with refractive indices of 1.611.61 and 1.651.65 for red and violet light, respectively. The material's dispersive power is 0.070.07. Under favourable conditions, a yellow light beam passing through the prism experiences a minimum deviation of 4.0^{}^{{}^{\circ}}. Determine the angle of the prism.

Options

  1. A5.0^{}^{{}^{\circ}}
  2. B7.0^{}^{{}^{\circ}}
  3. C6.3^{}^{{}^{\circ}}
  4. D8.0^{}^{{}^{\circ}}

Correct answer

B. 7.0^{}^{{}^{\circ}}

Step-by-step solution

The dispersive power ω\omega of the prism material is given by the formula:

ω=μv−μrμy−1\omega = \dfrac{\mu_v - \mu_r}{\mu_y - 1}

Substituting the given values:

0.07=1.65−1.61μy−10.07 = \dfrac{1.65 - 1.61}{\mu_y - 1}

μy−1=0.040.07=47\mu_y - 1 = \dfrac{0.04}{0.07} = \dfrac{4}{7}

For a thin prism, the deviation for yellow light is given by:

δy=(μy−1)A\delta_y = (\mu_y - 1)A

Given that \delta_y = 4.0^{}^{{}^{\circ}}, we can find the angle of the prism AA:

4.0^{}^{{}^{\circ}} = \left(\dfrac{4}{7}\right) A

A = \dfrac{4.0^{}^{{}^{\circ}} \times 7}{4} = 7.0^{}^{{}^{\circ}}
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