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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Fluid Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Fluid Mechanics

Two speakers S_1 and S_2 , powered by a common amplifier, are...

Two speakers S1S_1 and S2S_2, powered by a common amplifier, are situated at y=1.0 my = 1.0 \text{ m} and y=−1.0 my = -1.0 \text{ m} as shown in the figure. These speakers vibrate in phase at 600 Hz600 \text{ Hz}. A man is standing at a point on the X-axis located at a very large distance from the origin and begins to move parallel to the Y-axis. The speed of sound in air is given as 330 m s−1330 \text{ m s}^{-1}. At what angle θ\theta will the man experience a maximum of sound intensity for the first time?
Two speakers S_1 and S_2 , powered by a common amplifier, are situated at y = 1.0 m and y = -1.0 m as shown in the

Options

  1. A515 N/m2515 \text{ N/m}^2
  2. B500 N/m2500 \text{ N/m}^2
  3. C485 N/m2485 \text{ N/m}^2
  4. D470 N/m2470 \text{ N/m}^2

Correct answer

C. 485 N/m2485 \text{ N/m}^2

Step-by-step solution

The distance between the two speakers S1S_1 and S2S_2 is d=1.0−(−1.0)=2.0 md = 1.0 - (-1.0) = 2.0 \text{ m}.

The wavelength of the sound wave is given by:

λ=vf=330600=0.55 m\lambda = \dfrac{v}{f} = \dfrac{330}{600} = 0.55 \text{ m}

For a point at a very large distance from the origin at an angle θ\theta with the X-axis, the path difference between the sound waves reaching the man from S1S_1 and S2S_2 is:

Δx=dsin⁡θ\Delta x = d \sin \theta

The man starts from the X-axis (\theta = 0^{}^{{}^{\circ}}), where there is a central maximum. As he moves parallel to the Y-axis, he will experience the first maximum of sound intensity when the path difference equals one wavelength (λ\lambda).

Δx=λ\Delta x = \lambda

dsin⁡θ=λd \sin \theta = \lambda

Substituting the values, we get:

2.0sin⁡θ=0.552.0 \sin \theta = 0.55

sin⁡θ=0.552.0=0.275\sin \theta = \dfrac{0.55}{2.0} = 0.275

We know that \sin 15^{}^{{}^{\circ}} = \dfrac{\sqrt{3}-1}{2\sqrt{2}} \approx 0.259. Since 0.2750.275 is slightly greater than 0.2590.259, the angle θ\theta must be slightly greater than 15^{}^{{}^{\circ}}.

From the given options, the closest angle is 16^{}^{{}^{\circ}}.
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