A 1.00 m long pole stands half-dipped in a swimming pool where the water level is 50.0 cm above the bed. The refractive index of the water is 1.33 , and sunlight strikes at an angle of 45^ with the vertical. Determine the length of the pole's shadow on the bed.

Step-by-step solution

The total length of the pole is 100 cm . Since it is half-dipped in the pool, the length of the pole above the water surface is 50 cm and the length below the water surface is 50 cm . The sunlight strikes at an angle of 45^ with the vertical. The shadow cast by the portion of the pole above the water on the water surface has a length x₁ given by: x₁ = 50 45^ = 50 cm The light ray from the tip of the pole strikes the water surface at an angle of incidence i = 45^ . Let the angle of refraction be r . Applying Snell's