A convex lens has a focal length of 10 cm . Determine the location...

Given $f = +10 \text{ cm}$ and $u = -9.8 \text{ cm}$.

Using the lens formula:

$\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}$

$\dfrac{1}{v} = \dfrac{1}{f} + \dfrac{1}{u}$

$\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{9.8}$

$\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{10}{98}$

$\dfrac{1}{v} = \dfrac{49 - 50}{490}$

$\dfrac{1}{v} = -\dfrac{1}{490}$

$v = -490 \text{ cm}$

The negative sign indicates that the image is formed on the same side as the object. Since the image is formed by actual divergence of rays from the same side, it is virtual.

Therefore, the image is at $490 \text{ cm}$ on the side of the object and is virtual.