A pin of length 2.0 cm lies along the principal axis of a converging lens, with its centre positioned at a distance of 11 cm from the lens. The lens has a focal length of 6 cm . Determine the size of the image.

Step-by-step solution

Given: Length of the pin, L_o = 2.0 cm Focal length of the converging lens, f = +6 cm Distance of the centre of the pin from the lens = 11 cm Since the pin lies along the principal axis, its ends are located at distances of 11 - 1 = 10 cm and 11 + 1 = 12 cm from the optical centre of the lens. Thus, the object coordinates for the two ends are u₁ = -10 cm and u₂ = -12 cm . Using the lens formula, 1 v - 1 u = 1 f v = uf u+f For the first end ( u₁ = -10 cm ): v₁ = -10 6 -10 + 6 = -60 -4 = 15 cm For the second end ( u₂